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Question Detail
Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number
 17
 15
 8
 3
Answer: Option D
Explanation:
If the number is x,
Then, x + 17 = 60/x
x2 + 17x  60 = 0
(x + 20)(x  3) = 0
x = 3, 20, so x = 3 (as 3 is positive)
1. Find the number, when 15 is subtracted from 7 times the number, the result is 10 more than twice of the number
 5
 15
 7.5
 4
Answer: Option A
Explanation:
Let the number be x.
7x 15 = 2x + 10 => 5x = 25 => x = 5
2. Sum of a rational number and its reciprocal is 13/6. Find the number
 2
 3/2
 4/2
 5/2
Answer: Option B
Explanation:
\begin{aligned} => x + \frac{1}{x} = \frac{13}{6} \end{aligned}
\begin{aligned} => \frac{x^2+1}{x} = \frac{13}{6} \end{aligned}
\begin{aligned} => 6x^213x+6 = 0 \end{aligned}
\begin{aligned} => 6x^29x4x+6 = 0 \end{aligned}
\begin{aligned} => (3x2)(2x3) \end{aligned}
\begin{aligned} => x = 2/3 or 3/2 \end{aligned}
3. Product of two natural numbers is 17. Then, the sum of reciprocals of their squares is
 \begin{aligned} \frac{290}{289} \end{aligned}
 \begin{aligned} \frac{1}{289} \end{aligned}
 \begin{aligned} \frac{290}{90} \end{aligned}
 \begin{aligned} \frac{290}{19} \end{aligned}
Answer: Option A
Explanation:
If the numbers are a, b, then ab = 17,
as 17 is a prime number, so a = 1, b = 17.
\begin{aligned} \frac{1}{a^2} + \frac{1}{b^2} =
\frac{1}{1^2} + \frac{1}{17^2}
\end{aligned}
\begin{aligned} = \frac{290}{289}
\end{aligned}
4. find the number, difference between number and its 3/5 is 50.
 120
 123
 124
 125
Answer: Option D
Explanation:
Let the number = x,
Then, x(3/5)x = 50,
=> (2/5)x = 50 => 2x = 50*5,
=> x = 125
5. Difference between a twodigit number and the number obtained by interchanging the two digits is 36, what is the difference between two numbers
 2
 4
 8
 12
Answer: Option B
Explanation:
Let the ten digit be x, unit digit is y.
Then (10x + y)  (10y + x) = 36
=> 9x  9y = 36
=> x  y = 4.
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